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Old Nov 16th, 2004, 09:08 PM   #3
jjmoohead
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hmmm i have seen this before, but unfortunitly the only one i can remember at this time is that 1+1 = 1

a = 1
b = 1

a = b

a2 = b2 if a=b then the squars are exual

a2 - b2 = 0 move bsquared to other side of equation.

(a-b)(a+b) = 0 this is the algebric form of the previous equation

(a-b)(a+b)/(a-b) = 0/(a-b) what you do to one side you do to other.

1(a+b) = 0 anything divided by itself is 1 (a-b)/(a-b) becomes 1

(a+b) = 0 1 times anything is itself

1 + 1 = 0 a=1 b=1 already stated.

2 = 0 1 + 1 does equal 2....

Divide both sides by 2

1 = 0

Now we simply add 1 to both sides of the equation. (what you do to one side you must do to the other.

1 + 1 = 1

There is an explanation of this at a website..i think its DrMaths or something.

So I guess you could say 1+1 doesnt equal 3, it equals 1...lol
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